已知函数f(x)=ex-1,g(x)=x+x,其中e是自然对数的底,e=2.71
题型:解答题
问题:
已知函数f(x)=ex-1,g(x)=
(1)证明:函数h(x)=f(x)-g(x)在区间(1,2)上有零点; (2)求方程f(x)=g(x)根的个数,并说明理由; (3)若数列{an}(n∈N*)满足a1=a(a>0)(a为常数),f(an+1)=g(an),证明:存在常数M,使得对于任意n∈N*,都有an≤M. |
已知函数f(x)=ex-1,g(x)=
(1)证明:函数h(x)=f(x)-g(x)在区间(1,2)上有零点; (2)求方程f(x)=g(x)根的个数,并说明理由; (3)若数列{an}(n∈N*)满足a1=a(a>0)(a为常数),f(an+1)=g(an),证明:存在常数M,使得对于任意n∈N*,都有an≤M. |