变压器的硅钢片交错叠装和铁芯柱做成阶梯式的目的是什么?

题型:问答题 简答题

问题:

变压器的硅钢片交错叠装和铁芯柱做成阶梯式的目的是什么?

考点:电力生产“1000个为什么”电气运行与检修电气运行与检修题库
题型:问答题 简答题

“服务第一、销售第二”是当今发达国 * * 险经营管理的重要道德准则,为此,一些国家提出了不少深入人心的服务口号,如()保险业提出:“顾客就是公司的股东”。

A.美国

B.英国

C.德国

D.日本

题型:问答题 简答题

合同当事人互负债务,没有先后履行顺序的,一方在对方履行之前有权拒绝其履行要求。合同当事人的这种权利称为( ) 。

A.先履行抗辩权

B.同时履行抗辩权

C.后履行抗辩权

D.不安抗辩权

题型:问答题 简答题

任务型读写。阅读下面短文,根据所读内容在表格中的空白处填入恰当的单词。

注意:每个空格只填一个单词。

     Many people need guidance in choosing a career (职业). Fortunately, there is much information on the

Web about job opportunities (机会). With all the information available, it's not surprising that people can

feel confused. So if you're ready to start your first job or change careers, where do you begin?

     The Occupation Handbook is a good resource. Regularly updated, the Handbook is available as a book

and on-line. Not only is information provided about the United States as a whole, but readers can easily

search for information about their particular state. You can read about the fastest-growing occupations in

the area where you live and find out what they are like. You can also learn how to apply for jobs.

     Take, for example, Nadia's situation. Nadia was a doctor's assistant in Iran, and her goal in the United

States is to become a nurse. However, she needs to work while she is studying nursing. She is interested

in becoming a medical assistant to help work her way through college. When going on-line to the Handbook

and searching under "medical assistant", Nadia is happy to read that this is expected to be one of the fastest-

growing careers through 2010. Besides, job opportunities are even better for people with experience. She

discovers that medical assistants not only have to do some office work, but have medical responsibilities as

well. Nadia decides this job will be interesting and will also provide excellent experience for her nursing

career.

     The Occupation Handbook is just an example of websites that can help you plan a new career. When

you have found information about some different careers, you will be ready to talk to career advisers.

Choosing your future career is an extremely important decision. It's worth taking the time and finding as

much information as you can.

1_______  2_______  3_______  4_______  5_______

6_______  7_______  8_______  9_______  10_______

题型:问答题 简答题

某太阳能热水器中装有质量为50kg的水,在阳光的照射下,该热水器中水的温度从25℃升高到45℃.求这些水吸收的热量.[水的比热容为4.2×103J/(kg•℃)].

题型:问答题 简答题

已知数据文件IN.DAT中存有200个四位数,并已调用读函数readDat()把这些数存入数组a中。请编写函数jsVal(),其功能是:把千位数字和个位数字重新组成一个新的十位数(新十位数的十位数字是原四位数的千位数字,新十位数的个位数字是原四位数的个位数字),以及把百位数字和十位数字组成另一个新的十位数(新十位数的十位数字是原四位数的百位数字,新十位数的个位数字是原四位数的十位数字),如果新组成的两个十位数均是奇数并且两个十位数中至少有一个数能被5整除,同时两个新数的十位数字均不为零,则将满足此条件的四位数按从大到小的顺序存入数组b中,并计算满足上述条件的四位数的个数cnt。最后main()函数调用写函数writeDat(),把结果cnt以及数组b中符合条件的四位数输出到OUT.DAT文件中。
注意:部分源程序已经给出。
程序中已定义数组:a[200],b[200];已定义变量:cnt。
请勿改动数据文件IN.DAT中的任何数据及主函数main()、读函数readDat()和写函数writeDat()的内容。
#include<stdio.h>
#define MAX 200
int a[MAX],b[MAX],cnt=0;
void jsVal()


void readDat()

int i;
FILE *fp;
fp=fopen("IN.DAT","r");
for(i=0;i<MAX;i++)
fscanf(fp,"%d,",&a[i]);
fclose(fp);

void writeDat()

FILE *fp;
int i;
fp=fopen("OUT.DAT","w");
fprintf(fp,"%d\n",cnt);
for(i=0;i<cnt;i++)
fprintf(fp,"%d\n",b[i]);
fclose(fp);

void main()

int i;
readDat();
jsVal();
printf("满足条件的数=%d\n",cnt);
for(i=0;i<cnt;i++)
printf("%d",b[i]);
printf("\n");
writeDat();

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