题型:问答题 简答题 已知在1×105Pa,298 K条件下,2mol氢气燃烧生成水蒸气放出484 kJ热量,下列热化学方程式正确的是[ ]A.H2O(g)=H2(g)+1/2O2(g)△H = +242kJ/mol B.2H2(g)+O2(g)=2H2O(l)△H = -484kJ/mol C.H2(g)+1/2O2(g)=H2O (l)△H = -242 kJ/mol D.2H2(g)+O2(g)=2H2O(g)△H = +484 kJ/mol 查看答案