题型:名词解释 设函数y=f(ex)ef(x),其中f(x)可导,则dy=()。A.ef(x)[exf'(x)+f'(ex)]dxB.ef(x)[exf'(ex)+f(ex)f'(x)]dxC.ef(x)[f'(ex)+f(ex)f'(x)]dxD.ef(x)[f'(ex)+exf(ex)f'(x)]dx 查看答案