工程回访的方式不包括（）。A．季节性回访 B．经质量问题投诉后回访 C．技术性回访

下列描述中不符合"感知综合障碍"的涵义的是（）。

A.感知客观事物的个别属性，如大小、长短、远近时产生变形

B.感觉周围的人在监视自己

C.感觉周围的事物像"水中月"、"镜中花"

D.感觉自己的面孔或体形改变了形状

Here are some advertisements taken from a newspaper.

（1）

Dear Drew Carter,

Your first year on this earth has been a pleasure ride for all of us. We love you!

Dad and Mom

and many friends

（2）

Lawlis---Clarke

The Doctor Virgil and Marjorie Lawlis are pleased to announce the engagement of their daughter Diane Susan to Mr. Robert Brent Clarks, son of Mr. and Mrs. James Clarks of Herford, Texas.

A spring wedding is planned in House.

（3）

Isbell---Foss

Mr. and Mrs. Davis K. Isbell announce the marriage of their daughter Dang to Mr. Stanley Foss, son of Mrs. John Sipe of Ada, Minnessota.

The wedding will be early April at Abiding Love Lutheran Church.

（4）

Story－Kurio

Miss Stephanie Story and Mr. Todd Warren Kurio were married on February 5, at half past seven o'clock in the evening in Highland Park Prebytefian Church in Dallas, Texas. The bride is the daughter of Mr. and Mrs. Herbert Brue Story Jr. of Dallas. The groom is the son of Mr. and Mrs. Gerald Stanley Kurio of Austin.

小题1:What would be the best title for the first advertisement?

A．We Love You

B．Happy lst Birthday

C．One Year Old

D．Our One-Year-Old Son小题2:Lawlis and Clarke are going to get married___________.

A．in a church

B．where Clarke’s parents live

C．against their parents' will

D．to Lawlis’ parents' joy小题3:Who are now married couple?

A．Lawlis and Clarke

B．Dang Isbell and Foss

C．Story and Kurio

D．The text doesn't say.小题4:Who got or will get married in spring?

A．Not only Lawlis and Clarke but also Isbell and Foss

B．Neither Lawlis and Clarke nor Isbell and Foss

C．Either Isbell and Foss or Story and Kurio

D．Neither Lawlis and Clarke nor Story and Kurio

试述恶性综合征的临床特点。

头道拐断面流量降至50立方米每秒、利津断面流量降至（）立方米每秒时，启动黄河水量调度突发事件应急机制。

A、20

B、30

C、40

D、50

以下程序输出结果为______。 #include＜iostream＞ using namespace std; class TestClass 1 { public: TestClass1(){} TestClass1(int i) {x1=i;} void dispa() {cout＜＜"x1="＜＜x1＜＜",";} private: int x1; }: class TestClass2:public TestClass1 { public: TestClass2(){} TestClass2(int i):TestClass1(i+10) { x2=i: } void dispb() { dispa(); cout＜＜"x2="＜＜x2＜＜end1; } private: int x2: }: int main() { TestClass2 b(2): b.dispb(); return 0; }