25 ℃、101 kPa下，碳、氢气、甲烷和葡萄糖的燃烧热依次是ΔH＝－393.
题型：选择题
问题：
25 ℃、101 kPa下，碳、氢气、甲烷和葡萄糖的燃烧热依次是ΔH＝－393.5 kJ/mol、ΔH＝－285.8 kJ/mol、ΔH＝－890.3 kJ/mol、ΔH＝－2 800 kJ/mol，则下列热化学方程式正确的是( )
A．C(s)＋
O2(g)=CO(g)ΔH＝－393.5 kJ/mol
B．2H2(g)＋O2(g)=2H2O(l)ΔH＝－571.6 kJ/mol
C．CH4(g)＋2O2(g)=CO2(g)＋2H2O(g)ΔH＝－890.3 kJ/mol
D．C6H12O6(s)＋3O2(g)=3CO2(g)＋3H2O(g)ΔH＝－1 400 kJ/mol