患者,男,45岁,因进行性消瘦、上腹部饱胀、胃纳减退,近日肝区疼痛、发热来医院就诊,

题型:单项选择题 A1/A2型题

问题:

患者,男,45岁,因进行性消瘦、上腹部饱胀、胃纳减退,近日肝区疼痛、发热来医院就诊,查AFP650μg/L,HBsAg阳性,ALT151U/L,γ-GT252U/L,该病最有可能诊断为()

A.急性病毒性肝炎

B.慢性迁延性肝炎

C.肝硬化

D.原发性肝癌

E.转移性肝癌

考点:临床医学检验技术(师)临床化学检验综合练习临床化学检验综合练习题库
题型:单项选择题 A1/A2型题

恢复表中所有被逻辑删除记录的命令是______。

题型:单项选择题 A1/A2型题

关于惯性,下列说法正确的是(  )

A.只有在不受外力作用时物体才有惯性

B.只有运动的物体才具有惯性

C.惯性是指物体具有的保持原来静止或匀速直线运动状态的性质

D.两个物体只要速度相同,惯性就一定相同

题型:单项选择题 A1/A2型题

Austin Children’s Museum

This 7,000-square-foot museum aims to entertain and educate children up to age 9. In its Global City exhibit, people can go shopping for groceries, order lunch at a diner, pretend that they’re doctors or construction workers, and more. In other fun exhibits, they learn about Austin’s history, explore the world of water, and experience life on a large Texas farm.

Open time: From Tuesday to Saturday, 10:00 am~ 5:00 pm

On Sunday, 12:00 am ~ 5:00 pm

Address: 201 Colorado St, Austin, Texas 78701

Phone: 512-4722499

Brooklyn Children’s Museum

Founded in 1899, it is the world’s oldest children’s museum, featuring interactive exhibits,workshops and special events. The Mystery of Things teaches children about cultural and scientific objects and Music Mix welcomes young virtuosos(名家)。

Open time: From Wednesday to Friday, 2:00 pm ~ 5:00 pm

On Saturday and Sunday, 10:00am ~ 5:00 pm

Address: 145 Brooklyn Ave, Brooklyn, New York 1213

Phone: 718-7354400

Children’s Discovery Museum

This museum’s hand-on exhibits explore the relationships between the natural and the created worlds, and among people of different cultures and times. Exhibits include Streets, a  5/8-scale copy of an actual city, with street lights, and waterworks, which shows how pumps can move water through a reservoir system.

Open time: From Monday to Saturday, 10:00 am~ 5:00 pm

On Sunday, from noon. Closed on holidays.

Address: 180 Woz Way, Guadalupe River Park, San Jose, California 95110

Phone: 408-2985437

Children’s Museum of Indianapolis

This museum is the largest of its kind. Exhibits cover science, culture, space, history, and explorations. Among them are the Space Quest Planetarium ( additional fee),the 33-foot-high Water Clock, the Playscape gallery for preschools, and the Dinosphere exhibit, along with hand-on science exhibits. The largest gallery, the Center for Exploration, is designed for ages 12 and up.

Open time: From Tuesday to Sunday, 10:00 am ~ 5:00 pm

Closed on Thanksgiving Day and December 25.

Address: 3000 N Meridian St, Indianapolis, Indiana 46208

Phone: 317-3343322

72. Suppose that December 25 is Tuesday, which of the following museums can you visit?

A. Austin Children’s Museum.  

B. Brooklyn Children’s Museum.

C. Children’s Discovery Museum.  

D. Children’s Museum of Indianapolis.    

73. If you want to see how pumps can move water through a reservoir system, you should visit the museum in ___.

A. Texas   B. New York   C. California   D. Indiana

74. After entering the museum, you need to pay an additional fee to see ___.

A. the Center for Exploration    B. the Space Quest Planetarium

C. the Global City exhibit       D. Waterworks

75. The purpose of writing this passage is to ___.

A. ask adults to visit museums   

B. compare some museums and decide which one is the best

C. introduce some museums and encourage parents to visit them with their children

D. introduce some exhibits and museums to foreigners

题型:单项选择题 A1/A2型题


阅读以下关于Java企业级应用系统开发架构选择方面的叙述,在回答问题 1至问题3。
某软件公司承担了某中小型企业应用软件开发任务,进度要求紧迫。为了按时完成任务,选择合适的企业应用系统开发架构非常重要。项目组在进行方案论证时,项目组成员提出了两种开发思路。
(1)刘工建议采用J2EE 5.0和EJB 3.0进行开发。理由是J2EE定义了标准的应用开发体系结构和部署环境,EJB是J2EE的基础和核心。J2EE 5.0主要目标是简化开发,相比EJB 2.1,EJB 3.0具有很多改进和提高。
(2)杜工建议采用Struts,Spring和Hibernate轻量级开源框架相结合的方式。理由是随着Java开源项目阵营的发展壮大,一些基于POJOs (Plan Old Java Objects)的开源框架被广泛地引入到Java企业应用开发中来,与重量级的EJB框架相比,这些轻量级的框架有很多优点。
项目组仔细比较分析了两种方案的特点、优点和不足之处。认为杜工和刘工的建议都合理,但是从结合当前项目实际情况出发,最后决定采用杜工的建议。

【问题1】
Java企业应用框架一般被划分为三个层次,请用150字以内文字说明都有哪三个层次功能分别是什么

题型:单项选择题 A1/A2型题

在下面的Visual FoxPro表达式中,运算结果为逻辑真的是______。

A.EMPTY(.NUL)

B.LIKE('xy','xyz')

C.AT('xy','abcxyz')

D.ISNULL(SPACE(0))

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