阅读并回答问题。 孟浩然,字浩然,裹州襄阳人。少好节义,喜振人患难,隐鹿门山。

题型:阅读理解与欣赏

问题:

阅读并回答问题。

  孟浩然,字浩然,裹州襄阳人。少好节义,喜振人患难,隐鹿门山。年四十,乃游京师。尝于太学赋诗,一座嗟伏,无敢抗。张九龄、王维雅称道之。维私邀入内署,俄而玄宗至,浩然匿床下,维以实对,帝喜曰:“朕闻其人而未见也,何惧而匿?”诏浩然出。帝问其诗,浩然再拜,自诵所为,至“不才明主弃”之句,帝曰:“卿不求仕,而朕未尝弃卿,奈何诬我?”因放还。采访使韩朝宗的浩然偕至京师,欲荐诸朝。会故人至,剧饮欢甚。或曰:“君与韩公有期。”浩然叱曰:“业已饮,遑恤他!”卒不赴。朝宗怒,辞行,浩然不悔也。张九龄为荆州,辟置于府,府罢。开元末,病疽背卒。(选自《新唐书》)

1.解释下列句子中加粗的字。

(1)何惧而_________________

(2)浩然拜_________________

(3)采访使韩朝宗约浩然至京师_________________

(4)欲荐朝_________________

2.下列各组句子中加粗词语的意义和用法相同的一项是(     )

A.不赴/中往往语,皆指目陈胜

B.维以实/当窗理云鬓,镜帖花黄

C.朝宗怒,行/停数日,

D.君与韩公有/会天大雨,道不通,度已失

3.下列句子中加粗词语用法与“朕闻其人未见也”中的“而”相同的一项是(     )

A.黑质白章

B.启窗观,雕栏相望焉

C.年且九十,面山

D.先帝刨业未半中道崩殂

4.翻译文中划线的句子。

(1) 卿不求仕,而朕未尝弃卿,奈何诬我?

_________________________________________________________

(2)会故人至,剧饮欢甚。

_________________________________________________________

5.孟浩然是唐代著名的水田园诗人,但一生仕途坎坷。从全文看,他仕途坎坷的原因有哪些?

_________________________________________________________

考点:文言文阅读文言实词文言虚词一词多义翻译句子
题型:阅读理解与欣赏

With the spread of inter-active electronic media a man alone in his own home will never have been so well placed to fill the inexplicable mental space between cradle and crematorium. So I suspect that books will be pushed more and more into those moments of travel or difficult defecation (1) people still don’t quite know what to do with.

When people do read, I think they’ll want to feel they are reading literature, or (2) something serious. (3) you’re going to find fewer books presenting themselves as no-nonsense and (4) assuming literary pretensions and being packaged as works of art. We can expect an extraordinary variety of genre, but with an underlying (5) of sentiment and vision.

Translators can only (6) from this desire for the presumably sophisticated. We can look forward to lots of difficult names and fantastic stories of foreign parts enthusiastically (7) by the overall worship of the "global village’. Much of this will be awful and some wonderful, (8) don’t expect the press or the organizers of prizes to offer you much help in making the appropriate distinctions. They will be chiefly (9) in creating celebrity, the greatest enemy of discrimination, but a good prop for the (10) consumer.

Every ethnic grouping over the world will have to be seen to have a great writer—a phenomenon that will (11) a new kind of provincialism, more chronological than geographic, (12) only the strictly contemporary is talked about and (13) Universities, including Cambridge, will include (14) their literature syllabus novels, written only last year. (15) occasional exhumation for the Nobel, the achievements of ten or only five years ago will be largely forgotten.

In short, you can’t go too far wrong when predicting more of the same. But there is a (16) side to this—the inevitable reaction against it. The practical things I would like to see happen--publishers seeking less to (17) celebrity through extravagant advertising, (18) and magazines (19) space to reflective pieces—are rather more improbable than the Second Coming(耶稣复临). But dullness never quite darkens the whole planet. In their own idiosyncratic fashion a few writers will (20) be looking for new departures.

Read the following text. Choose the best word(s) for each numbered blank and mark A, B, C or D on ANSWER SHEET 1.19()

A.gives

B.giving

C.to give

D.give

题型:阅读理解与欣赏

辞退公安民警是公安机关的法定权力,只要符合法定条件,即可按照法定程序辞退,( )征得被辞退人员的同意。

A.必须

B.应当

C.无需

D.可以

题型:阅读理解与欣赏

漫画《败在媒体脚下》可以看出舆论监督(  )

A.是民主监督的新形式、新方法

B.能够引起中央领导人的关注

C.比其他监督方式更有效

D.具有透明度高、威力大的特点

题型:阅读理解与欣赏

[说明]
设一个环上有编号为0~n-1的n粒颜色不尽相同的珠子(每粒珠子颜色用字母表示,n粒珠子的颜色由输入的字符串表示)。从环上的某两粒珠子间剪开,则环上珠子形成一个序列然后按以下规则从序列中取走珠子:首先从序列左端取走所有连续的同色珠子; 然后从序列右端在剩下的珠子中取走所有连续的同色珠子,两者之和为该剪开处可取走珠子的粒数。在不同位置剪开,能取走的珠子也不尽相同。
本程序所求的是在环上哪个位置剪开,按上述规则可取走的珠子粒数最多。程序中用数组存储字符串。例如:10粒珠子颜色对应字符串为“aaabbbadcc”,在0号珠子前剪开,序列为aaabbbadcc,从左端取走3粒a色珠子,从右端取走2粒c色珠子,共取走5粒珠子。若在3号珠子前剪开,即bbbadccaaa,共取走6粒珠子。
[函数]
int count (char *s,int start,int end)
int i,c=0, color=s[start],step=(start>end)-1:1;
for i=start; s[i] ==color; i+=step)
if (step>0 && i>end || (1) ) break;
(2) ;

return c:

void main()
char t,s[120];
int i,j,c,len,maxc,cut=0;
printf("请输入环上代表不同颜色珠子字符串:");
scanf("%s”,s);
len=strlen(s);
for (i=maxc=0; i<len; i++)( /*尝试不同的剪开方式*/
c=count (s, 0,len-1);
if(c<len) c+=count( (3) );
if (c>maxc)cut=i; maxc=c;
/*数组s的元素循环向左移动一个位置*/
t=s[0];
for(j=1; j<len; j++) (4) ;
(5) ;

printf("在第%d号珠子前面剪开,可以取走%d个珠子.\n",cut,maxc);

题型:阅读理解与欣赏

老年人的膳食指南不包括()。

A.饮食多样化

B.主食中包括一定量的粗粮、杂粮

C.吃大豆及其制品

D.每天饮用牛奶或食用奶制品

E.多吃肉类,以补充必需氨基酸

更多题库