探索: (x-1)(x+1)=x2-1; (x-1)(x2+x+1)=x3-1;
问题:
探索:
(x-1)(x+1)=x2-1;
(x-1)(x2+x+1)=x3-1;
(x-1)(x3+x2+x+1)=x4-1;
(x-1)(x4+x3+x2+x+1)=x5-1;
(1)试求26+25+24+23+22+2+1的值;
(2) 22010+22009+22008+...+22+2+1的值的个位数是几?
探索:
(x-1)(x+1)=x2-1;
(x-1)(x2+x+1)=x3-1;
(x-1)(x3+x2+x+1)=x4-1;
(x-1)(x4+x3+x2+x+1)=x5-1;
(1)试求26+25+24+23+22+2+1的值;
(2) 22010+22009+22008+...+22+2+1的值的个位数是几?