In today’s world, English is the most wildly used language. It is our duty to learn English in the new situation of the reform and opening (改革开放) to the outside world. How can we master the English language ? I’d like to give you some good advice.
First, get interested in it. I enjoy listening to foreign friends talking when I was a child. At the same time I watched the English programme Follow Me on TV. From then on, I kept on learning English. The more I learned, the more progress I made.
Second, practice makes perfect. Many people study English very hard, but they are very shy to speak it in public, for they are afraid of making mistakes. Remember you have to make a mistake before you can correct it. A native English speaker makes mistakes sometimes, too.
Third, the beginners should be encouraged to pay attention to idioms. The English language has many idioms. For example, you should say “ He is as strong as a cow.”
小题1:The writer wants to tell us ____________.
A．the importance of learning English
B．the new situation of the reform and opening to the outside world
C．some good ideas on how to master English
D．the wide use of the English language小题2:If we want to learn English, we must first __________.
A．show interest in it
B．enjoy listening to it
C．watch English programmes on TV
D．practice speaking it小题3:When we are learning English, ____________.
A．remember the mistakes and correct them
B．try not to make any mistakes
C．avoid mistakes before making them
D．don’t be afraid of making mistakes小题4:The underlined sentence in Paragraph 3 means “_______________.”
A．Remember to make a mistake before you can correct it
B．You are sure to make a mistake before you can correct it
C．Remember you have to make a mistake and then correct it
D．You’ll make a mistake after you can correct it
所示，间距l＝0.3m的平行金属导轨a1b1c1和a2b2c2分别固定在两个竖直面内，在水平面a1b1b2a2区域内和倾角θ＝37°的斜面c1b1b2c2区域内分别有磁感应强度B1＝0.4T、方向竖直向上和B2＝1T、方向垂直于斜面向上的匀强磁场。电阻R＝0.3Ω、质量m1＝0.1kg、长为l的相同导体杆K、S、Q分别放置在导轨上，S杆的两端固定在b1、b2点，K、Q杆可沿导轨无摩擦滑动且始终接触良好。一端系于K杆中点的轻绳平行于导轨绕过轻质定滑轮自然下垂，绳上穿有质量m2＝0.05kg的小环。已知小环以a＝6m/s2的加速度沿绳下滑，K杆保持静止，Q杆在垂直于杆且沿斜面向下的拉力F作用下匀速运动。不计导轨电阻和滑轮摩擦，绳不可伸长。取g＝10m/s2，sin37°＝0.6，cos37°＝0.8。求：