设函数f(x)=x-a(x+1)ln(x+1),(x>-1,a≥0)(Ⅰ)求f(
题型:解答题
问题:
设函数f(x)=x-a(x+1)ln(x+1),(x>-1,a≥0) (Ⅰ)求f(x)的单调区间; (Ⅱ)当a=1时,若方程f(x)=t在[-
(Ⅲ)证明:当m>n>0时,(1+m)n<(1+n)m. |
设函数f(x)=x-a(x+1)ln(x+1),(x>-1,a≥0) (Ⅰ)求f(x)的单调区间; (Ⅱ)当a=1时,若方程f(x)=t在[-
(Ⅲ)证明:当m>n>0时,(1+m)n<(1+n)m. |