金银花自古被誉为清热解毒的良药,同时也是很多高级饮料的常用原料.“渝蕾一号”为重

题型:解答题

问题:

金银花自古被誉为清热解毒的良药,同时也是很多高级饮料的常用原料.“渝蕾一号”为重庆市中药研究院所选育的金银花优良品种,较传统金银花具有质量好、产量高、结蕾整齐等优点.某花农于前年引进一批“渝蕾一号”金银花种苗进行种植,去年第一次收获.因金银花入药或作饮料需要使用干燥花蕾,该花农将收获的新鲜金银花全部干燥成干花蕾后出售.根据经验,每亩鲜花蕾产量y(千克)与每亩种苗数x(株)满足关系式:y=-0.1x2+24.15x-440,每亩成本z(元)与每亩种苗数x(株)之间的函数关系满足下表:
每亩种苗数x(株)100110120130140
每亩成本z(元)18001860192019802040
(1)请观察题中的表格,用所学过的一次函数、反比例函数或二次函数的有关知识,求出z与x的函数关系式;
(2)若该品种金银花的折干率为20%(即每100千克鲜花蕾,干燥后可得20千克干花蕾),去年每千克干花蕾售价为200元,则当每亩种苗数x为多少时,每亩销售利润W可获得最大值,并求出该最大利润;(利润=收入-成本)
(3)若该花农按照(2)中获得最大利润的方案种植,并不断改善养植技术,今年每亩鲜花蕾产量比去年增加2a%.但由于市场上同类产品数量猛增,造成每千克干花蕾的售价比去年降低0.5a%,结果今年每亩销售总额为45810元.请你参考以下数据,估算出a的整数值(0<a<10).(参考数据:
5
≈2.24
6
≈2.45
7
≈2.65
8
≈2.83
考点:求二次函数的解析式及二次函数的应用
题型:解答题

Aldo is a manufacturer of specialist bottles with his factory in Italy. Bod is a Greek olive grower. Aldo entered into a contract with Bod to supply him with 10,000 bottles for his upcoming olive pressing. The bottles were specially made and packed by Aldo and as they were sold ‘ex works’ Bod arranged for a carrier to deliver the bottles to his warehouse in Greece. When the bottles arrived with Bod it was immediately apparent that they could not be used. They had been inadequately packed and many of them had been broken and the others had become contaminated during the journey from Italy to Greece and so could not be used as olive oil bottles.Bod immediately contacted Aldo to inform him that he would not pay for the bottles and that he would be getting replacements from a local supplier, although at a higher price. Aldo replied that he was not responsible for the damage, as it had occurred during the transportation of the bottles and he insists on full payment from Bod.Required:Advise Aldo and Bod as to their rights and liabilities under the UN Convention on Contracts for the International Sale of Goods, which may be assumed to apply to the transaction. (10 marks)

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34岁,女,近1年来经期持续时间延长,经量不多,伴经期腹痛,经期尚规律;既往月经规律,G1P0,IUD避孕。以下哪项诊断可能性最小()

A.排卵型功血

B.无排卵型功血

C.子宫肌瘤

D.IUD副作用

E.子宫内膜息肉

题型:解答题

关于变压器事故跳闸的处理原则,以下哪种说法是错的()

A、若主保护(瓦斯、差动等)动作,未查明原因消除故障前不得送电

B、如只是过流保护(或低压过流)动作,检查主变无问题可以送电

C、如因线路故障,保护越级动作引起变压器跳闸,则故障线路开关断开后,可立即恢复变压器运行

D、若系统需要,即使跳闸原因尚未查明,调度员仍可自行下令对跳闸变压器进行强送电

题型:解答题

生产的社会化包括( )。

A.生产资料使用的社会化

B.投资的社会化

C.生产过程的社会化

D.产品的社会化

题型:解答题

管道刚性接口不允许管道有轴向的交错,刚性接口抗震性能差,带型基础须设有变形缝。

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