观察下列式子. ①32-12=(3+1)(3-1)=8; ②52-32=(5+3
题型:解答题
问题:
观察下列式子.
①32-12=(3+1)(3-1)=8;
②52-32=(5+3)(5-3)=16;
③72-52=(7+5)(7-5)=24;
④92-72=(9+7)(9-7)=32.
(1)求212-192=______.
(2)猜想:任意两个连续奇数的平方差一定是______,并给予证明.
观察下列式子.
①32-12=(3+1)(3-1)=8;
②52-32=(5+3)(5-3)=16;
③72-52=(7+5)(7-5)=24;
④92-72=(9+7)(9-7)=32.
(1)求212-192=______.
(2)猜想:任意两个连续奇数的平方差一定是______,并给予证明.