把下列各式因式分 (1)-a2-1+2a=______; (2)2x2y-x3-
题型:解答题
问题:
把下列各式因式分
(1)-a2-1+2a=______;
(2)2x2y-x3-xy2=______;
(3)(x2+1)2-4x2=______;
(4)(x+y)2-2(x2-y2)+(x-y)2=______.
把下列各式因式分
(1)-a2-1+2a=______;
(2)2x2y-x3-xy2=______;
(3)(x2+1)2-4x2=______;
(4)(x+y)2-2(x2-y2)+(x-y)2=______.