数列{an}的前n项和为Sn,a1=1,Sn=12an+1(n∈N*).(1)求 发布时间:2017-05-03 20:14 │ 来源:www.tikuol.com 题型:解答题 问题: 数列{an}的前n项和为Sn,a1=1,Sn=12an+1(n∈N*).(1)求a2,a3.(2)求数列{an}的通项an;(3)求数列{nan}的前n项和Tn.
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