函数f(x)=a2x-ax+b x∈[-1,2],若f(0)=1,f(1)=34 发布时间:2017-05-03 00:45 │ 来源:www.tikuol.com 题型:解答题 问题: 函数f(x)=a2x-ax+b x∈[-1,2],若f (0)=1,f (1)=34,求(1)f (x)的解析式 (2)f (x)的值域 (3)f (x)的单调区间.
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