(5分)某实验小组为了测定人体呼出的气体中CO2的体积分数,设计如下实验: (1

题型:计算题

问题:

(5分)某实验小组为了测定人体呼出的气体中CO2的体积分数,设计如下实验:

(1)收集5L某同学呼出的气体样品;

(2)在气体样品中加入过量的澄清石灰水,振荡,充分反应;

(3)把反应后的物质全部转移到烧杯中,慢慢滴入质量分数为5%的稀盐酸,到不再产生气泡为止,产生气体的体积与加入盐酸的质量关系如图。

回答下列问题:

小题1:加入5.0g稀盐酸没有气泡产生,原因是(用化学方程式表示):                 

小题2:加入稀盐酸产生CO2的质量是多少?(溶于水中的CO2忽略不计)(写出计算过程)

小题3:该气体样品中CO2的体积分数是多少?(常温下CO2的密度约为2g/L,精确到0.1%)

考点:合成有机高分子材料
题型:计算题

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题型:计算题
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题型:计算题

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