已知等差数列{an}满足:a3=5,a4+a8=22.{an}的前n项和为sn.

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问题:

已知等差数列{an}满足:a3=5,a4+a8=22.{an}的前n项和为sn

(1)求数列{an}的通项公式;

(2)求使得sn>5n成立的最小正整数n的值.

(3)设cn=(-1)n+1•an•an+1,求数列{cn}的前n项和Tn

考点:等差数列的通项公式等差数列的前n项和
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