设f(x)是定义在R上的增函数,f(xy)=f(x)+f(y),f(3)=1,求 发布时间:2017-04-26 09:57 │ 来源:www.tikuol.com 题型:解答题 问题: 设f(x)是定义在R上的增函数,f(xy)=f(x)+f(y),f(3)=1,求解不等式f(x)+f(x-2)>1.
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