阅读短文,根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。选项中有一项

题型:阅读理解

问题:

阅读短文,根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。选项中有一项为多余选项。

     Do you like chocolate?           A box of it can be a great gift. Buy one for a friend and give it as a surprise.

See how happy that person gets.

     Say you just got a box of chocolate.            A man has studied people's choice. He says they tell something

about the person. Did you choose a round piece? You are a person who likes to party. Did you choose an oval

(椭圆形的) shape? You are a person who likes to make things. Picking a square shape shows something else.

The person is honest and truthful.           

     What kind of chocolate do you pick? Maybe you like milk chocolate. This shows you have warm feelings

about the past. Dark chocolate means something else. A person who chooses it looks toward the future. What

about white chocolate? Would you choose it?            Some people like chocolate with nuts (果仁). These are

people who like to help others.

     Do you believe these ideas? Can candy tell all these things? It doesn't really matter. There is one sure thing

about eaters of chocolate. They eat it because they like it.

A. You can depend on him or her.

B. Maybe most people do.

C. Which piece do you pick first?

D. If so, you may find it hard to make up your mind.

E. Because they are so sweet.

考点:日常生活类阅读
题型:阅读理解

血小板聚集试验增高见于()。

A.尿毒症

B.肝硬化

C.骨髓增生异常综合征

D.急性白血病

E.口服避孕药

题型:阅读理解

马奶酒是蒙古民族祭奠()的最重要的必备祭品之一。

题型:阅读理解

高血压同时有低血钾的病人首先要想到

A.垂体性Cushing病
B.原发性醛固酮增多症
C.嗜铬细胞瘤
D.肾动脉狭窄
E.甲亢伴周期性麻痹

题型:阅读理解

有以下程序
int f(int n)
if(n==1)return 1;
else return f(n-1)+1;
main()
int i,j=0;
for(i=1;i<3;i++)j+=f(i);
printf("%d\n",j);
程序运行后的输出结果是

A.4

B.3

C.2

D.1

题型:阅读理解

以下程序的功能是按顺序读入10名学生4门课程的成绩,计算出每位学生的平均分并输出,程序如下:  main( )  { int n,k;   float score,sum,ave;   sum=0.0;   for(n=1;n<=10;n++)   { for(k=1;k<=4;k++)    { scanf("%f",&score);sum+=score;}    ave=sum/4.0;    printf("NO%d:%f\n",n,ave);   }  }  上述程序运行后结果不正确,调试中发现有―条语句出现在程序中的位置不正确。这条语句是( )。

A.sum=0.0;

B.sum+=score;

C.ave=sum/4.0;

D.printf("NO%d:%f\n",n,ave);

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