求下列函数的值域:(1)y=x+2x+1;(2)y=x2-x+12x2-2x+3 发布时间:2017-04-20 19:44 │ 来源:www.tikuol.com 题型:解答题 问题: 求下列函数的值域:(1)y=x+2x+1;(2)y=x2-x+12x2-2x+3.
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