阅读理解。 Harry is from London.He is now in

题型:阅读理解

问题:

阅读理解。

     Harry is from London.He is now in China with his parents.He is thirteen years old.He is a student of Grade

Seven.

     Harry is a clever student.He works very hard.He is good at all his lessons.He says he likes Chinese best.

He speaks some Chinese now.A1l his teachers like him.They say he is a good student.

     Harry gets up at six twenty on weekdays.He has his breakfast at home.After breakfast.he walks to schoo1.

His school is about half a kilometer(公里)from his home.   School begins at Pen fifty every day.In the morning.

they have four classes.

     Harry, has lunch in the dining halt with his classmates. He usually has a short rest(休息)after lunch.They

have three classes in the afternoon.And school is over at four forty.

     After school,Harry plays ball games in the playground.   He goes home at about five thirty.He has a big

supper every day.In the evening.he does his homework and watches TV.And then he goes to bed at nine

thirty.

     Harry says he likes living in China very much."The people here are friendly and the food is nice.I like all

the things here."He says to his parents.

1.Harry is a boy from ________.

A.the USA        

B.China          

C.England          

D.Japan

2.Which subject does Harry 1ike best?

A.English        

B.Chinese        

C.math            

D.ball games

3.What time does Harry get up in the morning?

A.At six ten      

B.At seven fifty    

C.At six            

D.At six twenty

4.Where does he usually have lunch?

A.At home        

B.At school      

C.At a restaurant    

D.We don't know

5.What does he like in China?

A.The people      

B.The food        

C.All the things      

D.We don't know

考点:日常生活类阅读
题型:阅读理解
算一算。
10-7=7-3=
4+5=2+5=
7-0=8-6=
3+6=10-4=
0+10=7+3=
题型:阅读理解

发酵过程中,需对()进行灭菌

A、培养基

B、消泡剂

C、补加的物料

D、空气系统

E、管道与阀门

题型:阅读理解

甲股份有限公司从20×8年起按销售额的1%预提产品质量保证费用。该公司20×9年度前3个季度改按销售额的10%预提产品质量保证费用,并分别在20×9年度第1季度报告、半年度报告和第3季度报告中作了披露。该公司在编制20×9年年度财务报告时,董事会决定将第1季度至第3季度预提的产品质量保证费用全额冲回,并重新按20×9年度销售额的1%预提产品质量保证费用。假定以上事项均具有重大影响,且每年按销售额1%预提的产品质量保证费用与实际发生的产品质量保证费用大致相符,则甲股份有限公司在20×9年年度财务报告中对上述事项正确的会计处理方法是( )。

A.作为会计政策变更予以调整,并在会计报表附注中披露

B.作为会计估计变更予以调整,并在会计报表附注中披露

C.作为重要会计差错更正予以调整,并在会计报表附注中披露

D.不作为会计政策变更、会计估计变更或重要会计差错更正予以调整,不在会计报表附注中披露

题型:阅读理解

【说明】
栈(Stack)结构是计算机语言实现中的一种重要数据结构。对于任意栈,进行插入和删除操作的一端称为栈顶(Stock Top),而另一端称为栈底(Stock Bottom)。栈的基本操作包括:创建栈(NewStack)、判断栈是否为空(IsEmpty)、判断栈是否已满(IsFull)、获取栈顶数据(Top)、压栈/入栈(Push)、弹栈/出栈(Pop)。
当设计栈的存储结构时,可以采取多种方式。其中,采用链式存储结构实现的栈中各数据项不必连续存储(如下图所示)。


以下C代码采用链式存储结构实现一个整数栈操作。
【C代码】
typedef struct List
int data; //栈数据
struct List* next; //上次入栈的数据地址
List;
typedef struct Stack
List* pTop;//当前栈顶指针
Stack;
Stack* NewStack() return (Stack*) calloc(1/sizeof(Stack));
int IsEmpty(Stack* S)//判断栈S是否为空栈
if( (1) )return 1;
return 0;

int Top(Stack* s)//获取栈顶数据。若栈为空,则返回机器可表示的最小整数
if(IsEmpty(S))return INT_ MIN;
return (2)

void Push(Stack* S,int theData) //将数据theData压栈
List* newNode;
newNode=(List*)calloc(1/sizeof (List));
newNode->data=theData;
newNode->next=S->pTop;
S->pTop= (3)

void Pop(Stack* S) //弹栈
List* lastTop;
if(IsEmpty(S) ) return;
lastTop=S->pTop;
S->pTop= (4)
free(lastTop);

#define MD(a) a<<2
int main()
int i;
Stack* myStack;
myStack= NewStack();
Push(myStack,MD(1));
Push(myStack,MD(2));
Pop(myStack);
Push(myStack,MD(3)+1);
while( !IsEmpty(myStack) )
printf("%d",Top(myStack));
Pop(myStack);

return 0;

以上程序运行时的输出结果为: (5)

题型:阅读理解

公元500年,印度的科学家Susruta首次报告了()。

A.产褥感染

B.泌尿系统感染

C.产褥病率

D.产钳助产

E.麻醉学

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